(4x^2-10x-30x+75)10=(4x-3)(10x-75)-11(10x-75)

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Solution for (4x^2-10x-30x+75)10=(4x-3)(10x-75)-11(10x-75) equation: 



(4x^2-10x-30x+75)10=(4x-3)(10x-75)-11(10x-75)

We move all terms to the left:

(4x^2-10x-30x+75)10-((4x-3)(10x-75)-11(10x-75))=0

We multiply parentheses

40x^2-100x-300x-((4x-3)(10x-75)-11(10x-75))+750=0

We multiply parentheses ..

40x^2-((+40x^2-300x-30x+225)-11(10x-75))-100x-300x+750=0



We calculate terms in parentheses: -((+40x^2-300x-30x+225)-11(10x-75)), so:

(+40x^2-300x-30x+225)-11(10x-75)

We multiply parentheses

(+40x^2-300x-30x+225)-110x+825

We get rid of parentheses

40x^2-300x-30x-110x+225+825

We add all the numbers together, and all the variables

40x^2-440x+1050

Back to the equation:

-(40x^2-440x+1050)



We add all the numbers together, and all the variables

40x^2-400x-(40x^2-440x+1050)+750=0

We get rid of parentheses

40x^2-40x^2-400x+440x-1050+750=0

We add all the numbers together, and all the variables

40x-300=0

We move all terms containing x to the left, all other terms to the right

40x=300

x=300/40

x=7+1/2

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